main()
{
 
 /*
  * ++i -> i incremented before i is used.
  * --i -> i decremented before i is used.
  * j++ -> j is incremented AFTER j has been used. 
  * j-- -> j is decremented AFTER j has been used. 
  */
 
 int i=1,j=1;
 
 puts("\tDemo 1");
 printf("\t%d %d\n",++i, j++);   /* O/P  2 1 */
 printf("\t%d %d\n",i, j);    /* O/P  2 2 */
 
 i=1;j=1;
 
 puts("\n\tDemo 2");
 printf("\t%d \n",i=j++);    /* O/P  1 */
 printf("\t%d \n",i=++j);    /* O/P  3 */
 
 
 
 i = 0; j = 0;
 
 puts("\n\tDemo 3");
 if ( (i++ == 1) && (j++ == 1)) puts("Some text");
 
 /* Will i and j get incremented? The answer is NO! Because 
  * the expression in the left of '&&' resolves to false the 
  * compiler does NOT execute the expression on the right and 
  * so 'j' does not get executed!!!!! */
 
 
 printf("\t%d %d\n",i, j);    /* O/P 1 0 */
 
}